1957 AMC 12 Problem 10

Attempt Problem 10 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

The graph of y=2x2+4x+3y=2x^2+4x+3 has its:
lowest point at (−1,9)(-1,9)
lowest point at (1,1)(1,1)
lowest point at (−1,1)(-1,1)
highest point at (−1,9)(-1,9)
highest point at (−1,1)(-1,1)
Answer: C
Concepts:quadraticparabolacompleting the square
Small hint:
Complete the square in 2x2+4x+32x^2+4x+3
Big hint:
Because the coefficient of the square is positive, the vertex is a minimum
Solution:
Completing the square, y=2(x+1)2+1. y=2(x+1)^2+1. The squared term is nonnegative, so the graph has its lowest point at (−1,1).(-1,1).
Thus, the correct answer is C.
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