1957 AMC 12 Problem 19

Attempt Problem 19 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

The base of the decimal number system is ten, meaning, for example, that 123=1⋅102+2⋅10+3.123=1\cdot10^2+2\cdot10+3. In the binary system, which has base two, the first five positive integers are 1,1, 10,10, 11,11, 100,100, 101.101. The numeral 1001110011 in the binary system would then be written in the decimal system as:
1919
4040
1001110011
1111
77
Answer: A
Concepts:number baseplace valuepower of 2
Small hint:
Assign powers 24,23,…,202^4,2^3,\ldots,2^0 to the five binary places
Big hint:
Only the first, fourth, and fifth digits are nonzero
Solution:
Expanding by binary place value, (10011)2=1⋅24+1⋅21+1⋅20=16+2+1=19. \begin{aligned} (10011)_2 &=1\cdot2^4+1\cdot2^1+1\cdot2^0\\ &=16+2+1=19. \end{aligned}
Therefore, the correct answer is A.
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