1979 AMC 12 Problem 19

Attempt Problem 19 of the 1979 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1979 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

Find the sum of the squares of all real numbers satisfying the equation x256−25632=0.x^{256}-256^{32}=0.
88
128128
512512
65,53665{,}536
2(25632)2(256^{32})
Answer: A
Concepts:exponentperfect powerzero product property
Small hint:
Rewrite 25632256^{32} as a single power with exponent 256256
Big hint:
Determine the two real values whose 256256th powers equal 22562^{256}
Solution:
Since 256=28,256=2^8, 25632=2256. 256^{32}=2^{256}. Thus (x2)256=1.(\frac{x}{2})^{256}=1. The real solutions are x=2x=2 and x=−2,x=-2, and the sum of their squares is 4+4=8.4+4=8.
Therefore, the correct answer is A.
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