1963 AMC 12 Problem 19

Attempt Problem 19 of the 1963 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1963 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

In counting nn colored balls, some red and some black, it was found that 4949 of the first 5050 counted were red. Thereafter, 77 out of every 88 counted were red. If, in all, 90%90\% or more of the balls counted were red, the maximum value of nn is:
225225
210210
200200
180180
175175
Answer: B
Concepts:percentageinequalityrate
Small hint:
Write the number of red balls as 49+78(n−50)49+\frac78(n-50)
Big hint:
Require that quantity to be at least 0.9n0.9n
Solution:
The condition is 49+78(n−50)≥910n.49+\frac78(n-50)\geq\frac9{10}n. Simplifying gives 214≥n40,\frac{21}{4}\geq \frac{n}{40}, so n≤210.n\leq210. The maximum is 210.210.
Thus, the correct answer is B.
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