1957 AMC 12 Problem 23

Attempt Problem 23 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

The graph of x2+y=10x^2+y=10 and the graph of x+y=10x+y=10 meet in two points. The distance between these two points is:
less than 11
11
2\sqrt2
22
more than 22
Answer: C
Concepts:coordinate geometrydistance formulasystem of equations
Small hint:
Set the two expressions for yy equal
Big hint:
The resulting equation is x2=xx^2=x
Solution:
At an intersection, 10−x2=10−x, 10-x^2=10-x, so x=0x=0 or x=1.x=1. The points are (0,10)(0,10) and (1,9).(1,9). Their distance is (1−0)2+(9−10)2=2. \sqrt{(1-0)^2+(9-10)^2}=\sqrt2.
Therefore, the correct answer is C.
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