1961 AMC 12 Problem 23

Attempt Problem 23 of the 1961 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1961 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

Points PP and QQ are both in the line segment ABAB and on the same side of its midpoint. PP divides ABAB in the ratio 2:3,2:3, and QQ divides ABAB in the ratio 3:4.3:4. If PQ=2,PQ=2, then the length of ABAB is:
6060
7070
7575
8080
8585
Answer: B
Concepts:ratio and proportionfractionlinear equation
Small hint:
Express APAB\frac{AP}{AB} and AQAB\frac{AQ}{AB} from the two division ratios
Big hint:
Their difference is the fraction of ABAB represented by PQPQ
Solution:
The division ratios give APAB=25\frac{AP}{AB}=\frac25 and AQAB=37.\frac{AQ}{AB}=\frac37. Hence PQ=(37−25)AB=AB35.PQ=(\frac{3}{7}-\frac{2}{5})AB=\frac{AB}{35}. Since PQ=2,PQ=2, we obtain AB=70.AB=70.
Thus, the correct answer is B.
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