1983 AMC 12 Problem 23

Attempt Problem 23 of the 1983 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1983 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

In the adjoining figure the five circles are tangent to one another consecutively and to the lines L1L_1 and L2.L_2. If the radius of the largest circle is 1818 and that of the smallest one is 8,8, then the radius of the middle circle is
1212
12.512.5
1313
13.513.5
1414
Answer: A
Concepts:tangent circlessimilaritygeometric sequence
Small hint:
Every pair of consecutive tangent circles has the same shape after scaling
Big hint:
The radii form a geometric sequence, so the middle radius squared is the product of the extremes
Solution:
The centers lie on the angle bisector of L1L_1 and L2.L_2. Similarity of the configuration for any two consecutive circles shows that consecutive radii have a constant ratio. Thus the five radii form a geometric sequence. If the middle radius is m,m, symmetry of a five-term geometric sequence gives m2=8⋅18,m^2=8\cdot18, so m=12.m=12.
Therefore, the correct answer is A.
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