1964 AMC 12 Problem 12

Attempt Problem 12 of the 1964 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1964 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Which of the following is the negation of the statement: For all xx of a certain set, x2>0?x^2\gt0?
For all x,x, x2<0x^2\lt0
For all x,x, x2≤0x^2\leq0
For no x,x, x2>0x^2\gt0
For some x,x, x2>0x^2\gt0
For some x,x, x2≤0x^2\leq0
Answer: E
Concepts:logical deductioninequalitycounterexample
Small hint:
The negation of “for all” begins with “for some”
Big hint:
Negating x2>0x^2\gt0 gives x2≤0x^2\leq0
Solution:
The negation of a universal statement is an existential statement, and the negation of x2>0x^2\gt0 is x2≤0.x^2\leq0. Thus the negation is: for some x,x, x2≤0.x^2\leq0.
Therefore, the correct answer is E.
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