1977 AMC 12 Problem 12

Attempt Problem 12 of the 1977 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1977 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

Al’s age is 1616 more than the sum of Bob’s age and Carl’s age, and the square of Al’s age is 16321632 more than the square of the sum of Bob’s age and Carl’s age. The sum of the ages of Al, Bob and Carl is
6464
9494
9696
102102
140140
Answer: D
Concepts:difference of squaresages
Small hint:
Let ss be the sum of Bob’s and Carl’s ages
Big hint:
Factor a2−s2a^2-s^2 and use the known value of a−sa-s
Solution:
Let aa be Al’s age and ss the sum of the other two ages. Then a−s=16a-s=16 and 1632=a2−s2=(a−s)(a+s)=16(a+s). \begin{aligned} 1632&=a^2-s^2\\ &=(a-s)(a+s)\\ &=16(a+s). \end{aligned} Hence the requested total a+sa+s is 163216=102.\frac{1632}{16}=102.
Therefore, the correct answer is D.
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