1965 AMC 12 Problem 4

Attempt Problem 4 of the 1965 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1965 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Line l2l_2 intersects line l1l_1 and line l3l_3 is parallel to l1.l_1. The three lines are distinct and lie in a plane. The number of points equidistant from all three lines is:
00
11
22
44
88
Answer: C
Concepts:parallel linesangle bisectorcounting intersections
Small hint:
Points equidistant from the two parallel lines lie on their midway parallel
Big hint:
Intersect that midway line with the two angle bisectors of l1l_1 and l2l_2
Solution:
Points equidistant from parallel lines l1l_1 and l3l_3 lie on the unique line midway between them. Points equidistant from intersecting lines l1l_1 and l2l_2 lie on either of their two angle bisectors. Each angle bisector meets the midway parallel once, giving two points.
Therefore, the correct answer is C.
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