1967 AMC 12 Problem 17

Attempt Problem 17 of the 1967 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1967 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

If r1r_1 and r2r_2 are the distinct real roots of x2+px+8=0,x^2+px+8=0, then it must follow that:
∣r1+r2∣>42\lvert r_1+r_2\rvert\gt4\sqrt2
∣r1∣>3\lvert r_1\rvert\gt3 or ∣r2∣>3\lvert r_2\rvert\gt3
∣r1∣>2\lvert r_1\rvert\gt2 and ∣r2∣>2\lvert r_2\rvert\gt2
r1<0r_1\lt0 and r2<0r_2\lt0
∣r1+r2∣<42\lvert r_1+r_2\rvert\lt4\sqrt2
Answer: A
Concepts:quadraticVieta’s Formulasinequality
Small hint:
Distinct real roots require the discriminant to be positive
Big hint:
Use r1+r2=−pr_1+r_2=-p
Solution:
The discriminant condition is p2−32>0,p^2-32\gt0, so ∣p∣>42.\lvert p\rvert\gt4\sqrt2. By Vieta’s formulas, r1+r2=−p,r_1+r_2=-p, and therefore ∣r1+r2∣=∣p∣>42. \lvert r_1+r_2\rvert=\lvert p\rvert\gt4\sqrt2.
Therefore, the correct answer is A.
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