1969 AMC 12 Problem 10

Attempt Problem 10 of the 1969 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1969 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

The number of points equidistant from a circle and two parallel tangents to the circle is:
00
22
33
44
infinite
Answer: C
Concepts:circletangent linesymmetry
Small hint:
Points equidistant from the two parallel tangents lie on their midway parallel line
Big hint:
On that line, compare distance to either tangent with distance to the circle
Solution:
Let the circle have center OO and radius r.r. A point equidistant from the two parallel tangents must lie on their midline, which passes through O.O. If its distance from OO is t,t, its distance from either tangent is r,r, while its distance from the circle is ∣t−r∣.\lvert t-r\rvert. Thus ∣t−r∣=r,\lvert t-r\rvert=r, giving t=0t=0 or t=2r.t=2r. There is one point with t=0t=0 and two with t=2r,t=2r, for a total of 3.3.
Therefore, the correct answer is C.
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