1972 AMC 12 Problem 21

Attempt Problem 21 of the 1972 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1972 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

If the sum of the measures in degrees of angles A,A, B,B, C,C, D,D, E,E, and FF in the figure is 90n,90n, then nn is equal to:
22
33
44
55
66
Answer: C
Concepts:angle sumangle chasing
Small hint:
Name the two intersections of ADAD with BFBF and CECE
Big hint:
Combine the angle sums of the central quadrilateral and the two triangles attached to it
Solution:
Let P=AD∩BFP=AD\cap BF and Q=AD∩CE.Q=AD\cap CE. In quadrilateral EFPQ,EFPQ, E+F+∠P+∠Q=360∘. E+F+\angle P+\angle Q=360^\circ. The triangles BPDBPD and AQCAQC give B+D=∠PB+D=\angle P and A+C=∠Q,A+C=\angle Q, using the supplementary angles at PP and Q.Q. Adding yields A+B+C+D+E+F=360∘=90∘⋅4. \begin{gathered} A+B+C+D+E+F\\ =360^\circ=90^\circ\cdot4. \end{gathered} Thus n=4.n=4.
Therefore, the correct answer is C.
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