1973 AMC 12 Problem 35

Attempt Problem 35 of the 1973 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1973 AMC 12 solutions, or check the answer key.

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35.

In the unit circle shown in the figure, chords PQPQ and MNMN are parallel to the unit radius OROR of the circle with center at O.O. Chords MP,MP, PQ,PQ, and NRNR are each ss units long and chord MNMN is dd units long.
Of the three equations I.d−s=1,II.ds=1,III.d2−s2=5 \begin{array}{rl} \mathrm{I}.&d-s=1,\\ \mathrm{II}.&ds=1,\\ \mathrm{III}.&d^2-s^2=\sqrt5 \end{array} those which are necessarily true are
I\mathrm{I} only
II\mathrm{II} only
III\mathrm{III} only
I\mathrm{I} and II\mathrm{II} only
I,\mathrm{I}, II,\mathrm{II}, and III\mathrm{III}
Answer: E
Concepts:chordcircletrigonometric identityalgebraic manipulation
Small hint:
Use symmetry across the vertical diameter to see that the upper semicircle is divided into five equal chords
Big hint:
Write s=2sin⁡18∘s=2\sin18^\circ and d=2sin⁡54∘,d=2\sin54^\circ, then relate each to the square of the other
Solution:
Let KK be the left endpoint of the horizontal diameter. Reflection across the vertical diameter shows that KM=NR=sKM=NR=s and QN=MP=s.QN=MP=s. Together with the given equal chords, the upper semicircle is split into five equal arcs. Each subtends 36∘36^\circ at O.O. Thus s=2sin⁡18∘,d=2sin⁡54∘=2cos⁡36∘. \begin{aligned} s&=2\sin18^\circ,\\ d&=2\sin54^\circ\\ &=2\cos36^\circ. \end{aligned}
Using the double-angle identities, d=2(1−2sin⁡218∘)=2−s2,s=2cos⁡72∘=4cos⁡236∘−2=d2−2. \begin{aligned} d&=2(1-2\sin^218^\circ)\\ &=2-s^2,\\ s&=2\cos72^\circ\\ &=4\cos^236^\circ-2\\ &=d^2-2. \end{aligned} Adding these equations gives d+s=d2−s2=(d−s)(d+s). d+s=d^2-s^2=(d-s)(d+s). Since d+s>0,d+s\gt0, it follows that d−s=1.d-s=1. Substituting d=s+1d=s+1 into d=2−s2d=2-s^2 yields s2+s=1,s=5−12. s^2+s=1, \qquad s=\frac{\sqrt5-1}{2}. Therefore ds=s(s+1)=1 ds=s(s+1)=1 and d2−s2=(d−s)(d+s)=2s+1=5. \begin{aligned} d^2-s^2 &=(d-s)(d+s)\\ &=2s+1\\ &=\sqrt5. \end{aligned} All three equations are necessarily true.
Therefore, the correct answer is E.
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