1975 AMC 12 Problem 5

Attempt Problem 5 of the 1975 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1975 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

The polynomial (x+y)9(x+y)^9 is expanded in decreasing powers of x.x. The second and third terms have equal values when evaluated at x=px=p and y=q,y=q, where pp and qq are positive numbers whose sum is one. What is the value of p?p?
15\frac15
45\frac45
14\frac14
34\frac34
89\frac89
Answer: B
Concepts:binomial theoremlinear equation
Small hint:
Write the second and third binomial terms explicitly
Big hint:
After canceling common positive factors, combine p=4qp=4q with p+q=1p+q=1
Solution:
The terms are 9p8q9p^8q and 36p7q2.36p^7q^2. Their equality, with p,q>0,p,q\gt0, gives p=4q.p=4q. Since p+q=1,p+q=1, we get 5q=15q=1 and p=45.p=\frac{4}{5}.
Therefore, the correct answer is B.
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