1977 AMC 12 Problem 20

Attempt Problem 20 of the 1977 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1977 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

For how many paths consisting of a sequence of horizontal and/or vertical line segments, with each segment connecting a pair of adjacent letters in the diagram below, is the word CONTEST spelled out as the path is traversed from beginning to end?
6363
128128
129129
255255
none of these
Answer: E
Concepts:lattice pathssymmetrybasic counting
Small hint:
Reverse each path, starting from the central TT in the bottom row
Big hint:
Count the left-going and right-going families separately, then correct for their common path
Solution:
Reverse the paths and spell TSETNOC from the central bottom T.T. In the family whose horizontal moves go left, each of the six steps has two choices: up or left. This gives 26=642^6=64 paths. By symmetry, 6464 paths have horizontal moves going right. The all-vertical central path belongs to both families, so the total is 64+64−1=127. 64+64-1=127. This number is not among the first four choices.
Therefore, the correct answer is E.
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