1980 AMC 12 Problem 7

Attempt Problem 7 of the 1980 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1980 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Sides AB,AB, BC,BC, CD,CD, and DADA of convex polygon ABCDABCD have lengths 3,3, 4,4, 12,12, and 13,13, respectively; and ∠CBA\angle CBA is a right angle. The area of the quadrilateral is
3232
3636
3939
4242
4848
Answer: B
Concepts:Pythagorean Theoremright trianglearea decomposition
Small hint:
Draw diagonal ACAC and find its length from △ABC\triangle ABC
Big hint:
Recognize a second right triangle using the side lengths 5,5, 12,12, and 1313
Solution:
Triangle ABCABC is a 33-44-55 right triangle, so AC=5AC=5 and its area is 6.6. Since 52+122=132,5^2+12^2=13^2, triangle ACDACD is right at CC and has area (12)(5)(12)=30.(\frac{1}{2})(5)(12)=30. The quadrilateral’s area is 6+30=36.6+30=36.
Therefore, the correct answer is B.
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