1992 AMC 12 Problem 10

Attempt Problem 10 of the 1992 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

The number of positive integers kk for which the equation kx−12=3k kx-12=3k has an integer solution for xx is
33
44
55
66
77
Answer: D
Concepts:linear equationdivisibilitypositive divisors
Small hint:
Solve the equation for xx in terms of kk
Big hint:
The expression 3+12k3+\frac{12}{k} is integral exactly when kk is a positive divisor of 1212
Solution:
Solving gives x=3+12k.x=3+\frac{12}{k}. Thus xx is an integer precisely when kk is a positive divisor of 12.12. The possibilities are 1,1, 2,2, 3,3, 4,4, 6,6, and 12,12, for a total of 6.6.
Thus the correct answer is D.
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