1994 AMC 12 Problem 24

Attempt Problem 24 of the 1994 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1994 AMC 12 solutions, or check the answer key.

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24.

A sample consisting of five observations has an arithmetic mean of 1010 and a median of 12.12. The smallest value that the range (largest observation minus smallest) can assume for such a sample is
22
33
55
77
1010
Answer: C
Concepts:meanmedianrangeextremal construction
Small hint:
Order the observations as a≤b≤12≤d≤ea\le b\le12\le d\le e
Big hint:
Use the total sum 5050, then test whether a range below 55 is possible
Solution:
The sample 7,7,12,12,127,7,12,12,12 has sum 50,50, median 12,12, and range 5,5, so range 55 is possible. Suppose the range were at most 4.4. If the largest value were at most 12,12, then the top three values would all be 12,12, leaving the bottom two with sum 14;14; yet each would be at least 8,8, a contradiction. If the largest value exceeded 12,12, then the smallest would exceed 8,8, making the total exceed 8+8+12+12+12=52.8+8+12+12+12=52. Thus no smaller range works. The correct answer is C.
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