1995 AMC 12 Problem 10

Attempt Problem 10 of the 1995 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1995 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

The area of the triangle bounded by the lines

y=x,

y=-x

and

y=6

12

12\sqrt2

24

24\sqrt2

36

Find where each slanted line meets

y=6

Use the horizontal segment on

y=6

as the triangle’s base

The vertices are

(0,0),

(6,6),

and

(-6,6).

The horizontal base has length

12,

and the height is

6,

so the area is

\frac12(12)(6)=36.

Thus the correct answer is E.

Problem 10 in other years