1997 AMC 12 Problem 5

Attempt Problem 5 of the 1997 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1997 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

A rectangle with perimeter 176176 is divided into five congruent rectangles as shown in the diagram. What is the perimeter of one of the five congruent rectangles?
35.235.2
7676
8080
8484
8686
Answer: C
Concepts:similar dimensionsperimeter
Small hint:
Let the short and long sides of a small rectangle be xx and yy
Big hint:
The total width is both 3x3x across the top and 2y2y across the bottom
Solution:
Let a small rectangle have sides xx and y.y. The common width gives 3x=2y,3x=2y, while the large rectangle has dimensions 3x3x by x+y.x+y. Its perimeter is 2(4x+y)=176.2(4x+y)=176. Since y=3x2,y=\frac{3x}{2}, this is 11x=176,11x=176, so x=16x=16 and y=24.y=24. One small perimeter is 2(16+24)=80,2(16+24)=80, making C correct.
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