1950 AMC 12 Problem 2

Attempt Problem 2 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

Let

R=gS-4.

When

S=8,

R=16.

When

S=10,

R

is equal to:

11

14

20

21

None of these answers

First substitute the given values of

R

and

S

to determine

g

The first pair gives

16=8g-4

Substituting

S=8

and

R=16

gives

16=8g-4,

g=\tfrac52.

Hence, when

S=10,

R=\frac52(10)-4=21.

Thus, the correct answer is D.

Problem 2 in other years