1985 AMC 12 Problem 2

Attempt Problem 2 of the 1985 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1985 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

2.

In an arcade game, the “monster” is the shaded sector of a circle of radius 11 cm, as shown in the figure. The missing piece (the mouth) has central angle 60∘.60^\circ. What is the perimeter of the monster in cm?
π+2\pi+2
2π2\pi
53π\frac53\pi
56π+2\frac56\pi+2
53π+2\frac53\pi+2
Answer: E
Concepts:arccirclecircumferenceperimeter
Small hint:
The remaining circular arc has central angle 300∘300^\circ
Big hint:
Add the length of that arc to the two exposed radii
Solution:
The curved part is 300∘360∘=56\frac{300^\circ}{360^\circ}=\frac{5}{6} of a unit circle, so its length is (56)(2π)=5π3.(\frac{5}{6})(2\pi)=\frac{5\pi}{3}. The two straight sides of the mouth are radii of total length 2.2. Hence the perimeter is 5π3+2.\frac{5\pi}{3}+2.
Thus the correct answer is E.
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