1962 AMC 12 Problem 5

Attempt Problem 5 of the 1962 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1962 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

If the radius of a circle is increased by 11 unit, the ratio of the new circumference to the new diameter is:
π+2\pi+2
2π+12\dfrac{2\pi+1}{2}
π\pi
2π−12\dfrac{2\pi-1}{2}
π−2\pi-2
Answer: C
Concepts:circlecircumferenceratio and proportion
Small hint:
Call the new radius RR
Big hint:
Divide the circumference 2πR2\pi R by the diameter 2R2R
Solution:
For every circle, regardless of its radius, the circumference divided by the diameter is 2πR2R=π. \frac{2\pi R}{2R}=\pi.
Thus, the correct answer is C.
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