1963 AMC 12 Problem 21

Attempt Problem 21 of the 1963 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1963 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

The expression x2−y2−z2+2yz+x+y−zx^2-y^2-z^2+2yz+x+y-z has:
no linear factor with integer coefficients and integer exponents
the factor −x+y+z-x+y+z
the factor x−y−z+1x-y-z+1
the factor x+y−z+1x+y-z+1
the factor x−y+z+1x-y+z+1
Answer: E
Concepts:difference of squaresfactoringsubstitution
Small hint:
Group y−zy-z as a single expression
Big hint:
Rewrite the polynomial as x2−(y−z)2+x+(y−z)x^2-(y-z)^2+x+(y-z)
Solution:
Let u=y−z.u=y-z. The two groups factor as x2−u2=(x+u)(x−u),x+u=(x+u)⋅1. \begin{gathered} x^2-u^2=(x+u)(x-u),\\ x+u=(x+u)\cdot1. \end{gathered} Thus the whole expression is (x+u)(x−u+1),(x+u)(x-u+1), and one factor is x−y+z+1.x-y+z+1.
Therefore, the correct answer is E.
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