1964 AMC 12 Problem 18

Attempt Problem 18 of the 1964 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1964 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

Let nn be the number of pairs of values of bb and cc such that 3x+by+c=03x+by+c=0 and cx−2y+12=0cx-2y+12=0 have the same graph. Then nn is:
00
11
22
finite but more than 22
greater than any finite number
Answer: C
Concepts:system of equationsslopelogical deduction
Small hint:
Coincident line equations have proportional coefficient triples
Big hint:
Set (c,−2,12)=k(3,b,c)(c,-2,12)=k(3,b,c) and use the first and third coordinates
Solution:
For the same graph, (c,−2,12)=k(3,b,c).(c,-2,12)=k(3,b,c). Thus c=3kc=3k and 12=kc=3k2,12=kc=3k^2, so k=±2.k=\pm2. Each value determines one pair through b=−2kb=-\frac{2}{k} and c=3k.c=3k. Hence there are two pairs.
Therefore, the correct answer is C.
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