1966 AMC 12 Problem 12

Attempt Problem 12 of the 1966 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1966 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

The number of real values of xx that satisfy the equation
(26x+3)(43x+6)=84x+5 (2^{6x+3})(4^{3x+6})=8^{4x+5}
is:
00
11
22
33
greater than 33
Answer: E
Concepts:algebraic manipulationexponent
Small hint:
Rewrite every term with base 22
Big hint:
Compare the total exponent on each side before trying to solve for xx
Solution:
In base 2,2, the left exponent is (6x+3)+2(3x+6)=12x+15, \begin{aligned} &(6x+3)+2(3x+6)\\ &\qquad=12x+15, \end{aligned} and the right exponent is 3(4x+5)=12x+15.3(4x+5)=12x+15. The equation is an identity for every real x,x, so it has more than three real solutions.
Therefore, the correct answer is E.
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