1967 AMC 12 Problem 12

Attempt Problem 12 of the 1967 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1967 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

12.

If the (convex) area bounded by the xx-axis and the lines y=mx+4,y=mx+4, x=1,x=1, and x=4x=4 is 7,7, then mm equals:
−12-\dfrac12
−23-\dfrac23
−32-\dfrac32
−2-2
none of these
Answer: B
Concepts:coordinate geometrytrapezoidlinear equation
Small hint:
The parallel vertical sides have lengths m+4m+4 and 4m+44m+4
Big hint:
Their separation is 33, so use the trapezoid-area formula
Solution:
The bounded region is a trapezoid with parallel sides m+4m+4 and 4m+4,4m+4, separated by 3.3. Thus 32((m+4)+(4m+4))=7. \frac32\bigl((m+4)+(4m+4)\bigr)=7. Hence 15m+24=14,15m+24=14, so m=−23.m=-\frac{2}{3}. The endpoint heights are positive, as required for the stated convex region.
Therefore, the correct answer is B.
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