1971 AMC 12 Problem 26

Attempt Problem 26 of the 1971 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1971 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

26.

In triangle ABC,ABC, point FF divides side ACAC in the ratio 1:2.1:2. Let EE be the point where side BCBC meets AG,AG, where GG is the midpoint of BF.BF. Then EE divides BCBC in the ratio:
1:41:4
1:31:3
2:52:5
4:114:11
3:83:8
Answer: B
Concepts:mass pointsmidpointratio and proportion
Small hint:
Assign endpoint masses so that AF:FC=1:2AF:FC=1:2
Big hint:
The midpoint condition makes the masses at BB and FF equal
Solution:
Use mass points. Since AF:FC=1:2,AF:FC=1:2, assign masses 22 and 11 to AA and C,C, so the mass at FF is 3.3. Because GG is the midpoint of BF,BF, the mass at BB is also 3.3. Therefore BE:EC=mC:mB=1:3. BE:EC=m_C:m_B=1:3.
Therefore, the correct answer is B.
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