1958 AMC 12 Problem 26

Attempt Problem 26 of the 1958 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1958 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

26.

A set of nn numbers has the sum s.s. Each number of the set is increased by 20,20, then multiplied by 5,5, and then decreased by 20.20. The sum of the numbers in the new set thus obtained is:
s+20ns+20n
5s+80n5s+80n
ss
5s5s
5s+4n5s+4n
Answer: B
Concepts:distributive propertysummation
Small hint:
Apply all three operations to a typical original number uu
Big hint:
After simplifying the transformed number, sum over all nn entries
Solution:
An original number uu becomes 5(u+20)−20=5u+80. 5(u+20)-20=5u+80. Summing over the nn original numbers therefore gives 5s+80n. 5s+80n.
Thus, the correct answer is B.
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