1973 AMC 12 Problem 26

Attempt Problem 26 of the 1973 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1973 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

26.

The number of terms in an A.P. (Arithmetic Progression) is even. The sums of the odd- and even-numbered terms are 2424 and 30,30, respectively. If the last term exceeds the first by 10.5,10.5, the number of terms in the A.P. is
2020
1818
1212
1010
88
Answer: E
Concepts:arithmetic sequencesystem of equationspairing and grouping
Small hint:
Write the number of terms as 2n2n and the common difference as dd
Big hint:
Pair each odd-numbered term with the following even-numbered term to get nd=6nd=6
Solution:
Let the progression have 2n2n terms and common difference d.d. Pairing each odd-numbered term with its successor shows that nd=30−24=6. nd=30-24=6. The difference between the last and first terms is (2n−1)d=10.5. (2n-1)d=10.5. Since 2nd=12,2nd=12, subtraction gives d=1.5.d=1.5. Hence n=61.5=4,n=\frac{6}{1.5}=4, and the progression has 2n=82n=8 terms.
Therefore, the correct answer is E.
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