1972 AMC 12 Problem 6

Attempt Problem 6 of the 1972 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1972 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

If 32x+9=10(3x),3^{2x}+9=10(3^x), then the value of x2+1x^2+1 is:
11 only
55 only
11 or 55
22
1010
Answer: C
Concepts:exponentquadraticsubstitutionfactoring
Small hint:
Set u=3xu=3^x
Big hint:
Factor u2−10u+9u^2-10u+9 and convert each positive root back to xx
Solution:
Let u=3x.u=3^x. Then u2−10u+9=(u−1)(u−9)=0. \begin{aligned} u^2-10u+9&=(u-1)(u-9)\\ &=0. \end{aligned} Thus x=0x=0 or x=2,x=2, so x2+1x^2+1 is respectively 11 or 5.5.
Therefore, the correct answer is C.
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