1974 AMC 12 Problem 11

Attempt Problem 11 of the 1974 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1974 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

If (a,b)(a,b) and (c,d)(c,d) are two points on the line whose equation is y=mx+k,y=mx+k, then the distance between (a,b)(a,b) and (c,d),(c,d), in terms of a,a, c,c, and m,m, is
∣a−c∣1+m2|a-c|\sqrt{1+m^2}
∣a+c∣1+m2|a+c|\sqrt{1+m^2}
∣a−c∣1+m2\frac{|a-c|}{\sqrt{1+m^2}}
∣a−c∣(1+m2)|a-c|(1+m^2)
∣a−c∣∣m∣|a-c||m|
Answer: A
Concepts:coordinate geometrydistance formula
Small hint:
Use the line equation to express b−db-d in terms of a−ca-c
Big hint:
Substitute b−d=m(a−c)b-d=m(a-c) into the distance formula
Solution:
Since both points are on the line, b−d=m(a−c).b-d=m(a-c). Their distance is therefore ℓ=(a−c)2+(b−d)2=(a−c)2(1+m2)=∣a−c∣1+m2. \begin{aligned} \ell&=\sqrt{(a-c)^2+(b-d)^2}\\ &=\sqrt{(a-c)^2(1+m^2)}\\ &=|a-c|\sqrt{1+m^2}. \end{aligned}
Therefore, the correct answer is A.
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