1978 AMC 12 Problem 19

Attempt Problem 19 of the 1978 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1978 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

19.

A positive integer nn not exceeding 100100 is chosen in such a way that if n≤50,n\le50, then the probability of choosing nn is p,p, and if n>50,n\gt50, then the probability of choosing nn is 3p.3p. The probability that a perfect square is chosen is
0.050.05
0.0650.065
0.080.08
0.090.09
0.10.1
Answer: C
Concepts:basic probabilityperfect squarecounting integers in a range
Small hint:
First use the total probability to determine pp
Big hint:
Count the perfect squares at most 5050 and those from 5151 through 100100 separately
Solution:
The total probability is 50p+50(3p)=200p=1,50p+50(3p)=200p=1, so p=0.005.p=0.005. There are seven perfect squares at most 5050 and three more, 64,64, 81,81, 100,100, above 50.50. Hence the desired probability is 7p+3(3p)=16p=0.08. 7p+3(3p)=16p=0.08.
Therefore, the correct answer is C.
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