1984 AMC 12 Problem 21

Attempt Problem 21 of the 1984 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1984 AMC 12 solutions, or check the answer key.

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21.

The number of triples (a,b,c)(a,b,c) of positive integers which satisfy the simultaneous equations ab+bc=44,ac+bc=23. \begin{aligned} ab+bc&=44,\\ ac+bc&=23. \end{aligned} is
00
11
22
33
44
Answer: C
Concepts:Diophantine Equationfactorsubstitution
Small hint:
Factor the second equation as c(a+b)=23c(a+b)=23
Big hint:
Use the primality of 2323 and positivity to determine cc and a+ba+b
Solution:
Since c(a+b)=23c(a+b)=23 and all variables are positive integers, c=1c=1 and a+b=23.a+b=23. Put b=23−ab=23-a in ab+b=44.ab+b=44. Then (23−a)(a+1)=44, (23-a)(a+1)=44, or a2−22a+21=0,a^2-22a+21=0, so a=1a=1 or 21.21. Each gives a positive b,b, producing exactly two triples.
Therefore, the correct answer is C.
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