1989 AMC 12 Problem 21

Attempt Problem 21 of the 1989 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

A square flag has a red cross of uniform width with a blue square in the center on a white background as shown. (The cross is symmetric with respect to each of the diagonals of the square.) If the entire cross (both the red arms and the blue center) takes up 36%36\% of the area of the flag, what percent of the area of the flag is blue?
0.50.5
11
22
33
66
Answer: C
Concepts:area decompositionpercentagesymmetry
Small hint:
Let hh be half a diagonal of the central blue square after scaling the flag side to 11
Big hint:
The four white corner triangles together have area (1−2h)2(1-2h)^2
Solution:
Scale the flag to a unit square, and let hh be the horizontal distance from its center to a vertex of the blue square. The four congruent white corner triangles have total area (1−2h)2.(1-2h)^2. Since the cross occupies 0.36,0.36, (1−2h)2=0.64. (1-2h)^2=0.64. With 0<h<12,0\lt h\lt\frac{1}{2}, this gives h=0.1.h=0.1. The blue square has perpendicular diagonals 2h2h and 2h,2h, so its area is 12(2h)2=2h2=0.02,\frac12(2h)^2=2h^2=0.02, or 2%2\% of the flag.
Thus the correct answer is C.
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