1952 AMC 12 第 40 题

先试着解答 1952 AMC 12 第 40 题,然后核对你的答案与精心整理的解答,解答来自 LIVE by Po-Shen Loh。你也可以参加完整限时模拟考试、查看全部 1952 AMC 12 解答,或核对答案。

所有题目均经美国数学协会(MAA)官方合法授权使用。

40.

为了绘制 f(x)=ax2+bx+cf(x)=ax^2+bx+c 的图像,人们制作了一张数值表。对于一组等距递增的 xx 值,函数值依次为 38443844、39693969、40964096、42274227、43564356、44894489、46244624 和 47614761。其中不正确的是:
In order to draw a graph of f(x)=ax2+bx+c,f(x)=ax^2+bx+c, a table of values was constructed. These values of the function for a set of equally spaced increasing values of xx were 3844,3844, 3969,3969, 4096,4096, 4227,4227, 4356,4356, 4489,4489, 4624,4624, and 4761.4761. The one which is incorrect is:
40964096
43564356
44894489
47614761
以上均不是
None of these
答案:E
知识点:二次方程找规律完全平方数
小提示:
二次函数在等距输入值处的函数值具有恒定的二阶差
A quadratic sampled at equally spaced inputs has constant second differences
大提示:
相邻数值还表明它们可能是连续的完全平方数;先检查表中每个数值,再查看错误值是否出现在选项中
The surrounding values also suggest consecutive perfect squares; check every displayed table value before checking which values appear among the choices
解答:
这些数值应当是连续的平方数 622,632,642,652,662,672,682,692。 \begin{gathered} 62^2,63^2,64^2,65^2,\\ 66^2,67^2,68^2,69^2 \end{gathered}\text{。}即 3844,3969,4096,42253844,3969,4096,4225、4356,4489,4624,47614356,4489,4624,4761。因此,表中错误的数值是 42274227,但它不在选项 A–D 中。
所以,列出的四个数都不是错误值,正确答案是 E。
The values are intended to be the consecutive squares 622,632,642,652,662,672,682,692. \begin{gathered} 62^2,63^2,64^2,65^2,\\ 66^2,67^2,68^2,69^2. \end{gathered} These are 3844,3969,4096,4225,3844,3969,4096,4225, 4356,4489,4624,4761.4356,4489,4624,4761. Thus the incorrect table entry is 4227,4227, but it is not one of choices A-D.
Consequently none of the four listed numbers is incorrect, so the correct answer is E.
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