1950 AMC 12 Problem 26

Attempt Problem 26 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

26.

If log⁡10m=b−log⁡10n,\log_{10}m=b-\log_{10}n, then m=m=
bn\dfrac{b}{n}
bnbn
10bn10^bn
b−10nb-10^n
10bn\dfrac{10^b}{n}
Answer: E
Concepts:logarithmalgebraic manipulation
Small hint:
Move log⁡10n\log_{10}n to the left side
Big hint:
Combine the two logarithms and then exponentiate with base 1010
Solution:
Rearranging and using the product rule for logarithms gives log⁡10m+log⁡10n=log⁡10(mn)=b. \begin{aligned} &\log_{10}m+\log_{10}n\\ &=\log_{10}(mn)=b. \end{aligned} Therefore mn=10b,mn=10^b, so m=10bn.m=\dfrac{10^b}{n}.
Thus, the correct answer is E.
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