1951 AMC 12 Problem 1

Attempt Problem 1 of the 1951 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1951 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

The percent that

M

is greater than

N

is:

\dfrac{100(M-N)}{M}

\dfrac{100(M-N)}{N}

\dfrac{M-N}{N}

\dfrac{M-N}{M}

\dfrac{100(M+N)}{N}

Percent increase is measured relative to the original quantity

Here

N

is the original quantity, and the increase is

M-N

The increase from

N

M

M-N.

Dividing by the original quantity and multiplying by

100

gives

\frac{100(M-N)}{N}.

Thus, the correct answer is B.

Problem 1 in other years