1984 AMC 12 Problem 1

Attempt Problem 1 of the 1984 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1984 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

100022522−2482\frac{1000^2}{252^2-248^2} equals
62,50062{,}500
10001000
500500
250250
12\frac12
Answer: C
Concepts:difference of squaresalgebraic manipulation
Small hint:
Factor the denominator as a difference of squares
Big hint:
Use 252+248=500252+248=500 and 252−248=4252-248=4
Solution:
Factoring the denominator gives 2522−2482=(252+248)⋅(252−248)=500⋅4=2000. \begin{aligned} 252^2-248^2 &=(252+248)\\ &\quad{}\cdot(252-248)\\ &=500\cdot4=2000. \end{aligned} Thus the given quotient is 100022000=500.\frac{1000^2}{2000}=500. Therefore, the correct answer is C.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.