1980 AMC 12 Problem 1

Attempt Problem 1 of the 1980 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1980 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

The largest whole number such that seven times the number is less than 100100 is
1212
1313
1414
1515
1616
Answer: C
Concepts:inequalitywhole number operations
Small hint:
Translate “seven times the number is less than 100100” into an inequality
Big hint:
Locate 1007\frac{100}{7} between two consecutive whole numbers
Solution:
The number must be less than 1007=14+27.\frac{100}{7}=14+\frac{2}{7}. The largest whole number below this value is 14.14.
Therefore, the correct answer is C.
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