1974 AMC 12 Problem 1

Attempt Problem 1 of the 1974 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1974 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

If x≠0x\ne0 or 44 and y≠0y\ne0 or 6,6, then 2x+3y=12\frac2x+\frac3y=\frac12 is equivalent to
4x+3y=xy4x+3y=xy
y=4x6−yy=\frac{4x}{6-y}
x2+y3=2\frac{x}{2}+\frac{y}{3}=2
4yy−6=x\frac{4y}{y-6}=x
none of these
Answer: D
Concepts:rational equationfactoring
Small hint:
Clear all three denominators at once
Big hint:
After multiplying by 2xy,2xy, isolate the terms containing xx and factor
Solution:
Multiplying by 2xy2xy gives 4y+6x=xy,4y+6x=xy, so 4y=x(y−6).4y=x(y-6). Since y≠6,y\ne6, x=4yy−6. x=\frac{4y}{y-6}.
Therefore, the correct answer is D.
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