1954 AMC 12 Problem 13

Attempt Problem 13 of the 1954 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1954 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

A quadrilateral is inscribed in a circle. If angles are inscribed in the four arcs cut off by the sides of the quadrilateral, without intersecting the sides between vertices, their sum will be:
180∘180^\circ
540∘540^\circ
360∘360^\circ
450∘450^\circ
1080∘1080^\circ
Answer: B
Concepts:inscribed anglearcangle sum
Small hint:
Let the four consecutive arc measures be a,b,c,da,b,c,d
Big hint:
An angle whose vertex lies in the arc of measure aa intercepts the other three arcs, of total measure 360∘−a360^\circ-a
Solution:
Let the four arcs have measures a,b,c,d,a,b,c,d, whose sum is 360∘.360^\circ. The angle placed in the arc of measure aa intercepts the other three arcs, so it measures 360∘−a2,\frac{360^\circ-a}{2}, and similarly for the others. Their sum is 4(360∘)−(a+b+c+d)2=1080∘2=540∘. \begin{aligned} &\frac{4(360^\circ)-(a+b+c+d)}2\\ &\qquad=\frac{1080^\circ}{2}\\ &\qquad=540^\circ. \end{aligned}
Thus, the correct answer is B.
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