1970 AMC 12 Problem 13

Attempt Problem 13 of the 1970 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1970 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

13.

Given the binary operation ∗* defined by a∗b=aba*b=a^b for all positive numbers aa and b.b. Then for all positive a,a, b,b, c,c, n,n, we have:
a∗b=b∗aa*b=b*a
a∗(b∗c)=(a∗b)∗ca*(b*c)=(a*b)*c
a∗(bn)=(a∗n)∗ba*(b^n)=(a*n)*b
(a∗b)n=a∗(bn)(a*b)^n=a*(bn)
None of these
Answer: D
Concepts:custom operationexponentalgebraic manipulation
Small hint:
Replace every ∗* using the definition before comparing the two sides
Big hint:
For choice D, both sides simplify to a power with exponent bnbn
Solution:
For choice D, (a∗b)n=(ab)n=abn,a∗(bn)=abn. \begin{aligned} (a*b)^n&=(a^b)^n=a^{bn},\\ a*(bn)&=a^{bn}. \end{aligned} Thus that identity always holds. The other choices would assert false general identities such as ab=baa^b=b^a or abc=abc.a^{b^c}=a^{bc}.
Therefore, the correct answer is D.
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