1957 AMC 12 Problem 11

Attempt Problem 11 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

11.

The angle formed by the hands of a clock at 2:152:15 is:
30∘30^\circ
2712∘27\frac12^\circ
15712∘157\frac12^\circ
17212∘172\frac12^\circ
none of these
Answer: E
Concepts:clockangle chasing
Small hint:
At 2:15,2:15, the minute hand is at 90∘90^\circ from twelve
Big hint:
The hour hand has advanced one quarter of the 30∘30^\circ interval from two to three
Solution:
The minute hand is 90∘90^\circ clockwise from twelve. The hour hand is 2(30∘)+14(30∘)=67.5∘ 2(30^\circ)+\frac14(30^\circ)=67.5^\circ from twelve. Their smaller angle is 90∘−67.5∘=22.5∘,90^\circ-67.5^\circ=22.5^\circ, which is not listed.
Therefore, the correct answer is E.
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