1958 AMC 12 Problem 25

Attempt Problem 25 of the 1958 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1958 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

25.

If log⁡kx⋅log⁡5k=3,\log_kx\cdot\log_5k=3, then xx equals:
k6k^6
5k35k^3
k3k^3
243243
125125
Answer: E
Concepts:logarithmalgebraic manipulationexponent
Small hint:
Use the chain identity log⁡kx⋅log⁡5k=log⁡5x\log_kx\cdot\log_5k=\log_5x
Big hint:
Convert the resulting logarithmic equation to exponential form
Solution:
By the change-of-base identity, log⁡kx⋅log⁡5k=log⁡5x. \log_kx\cdot\log_5k=\log_5x. Hence log⁡5x=3,\log_5x=3, so x=53=125.x=5^3=125.
Thus, the correct answer is E.
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