1959 AMC 12 Problem 18

Attempt Problem 18 of the 1959 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1959 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

The arithmetic mean (average) of the first nn positive integers is:
n2\dfrac n2
n22\dfrac{n^2}{2}
nn
n−12\dfrac{n-1}{2}
n+12\dfrac{n+1}{2}
Answer: E
Concepts:arithmetic sequencemean
Small hint:
Use the sum 1+2+⋯+n1+2+\cdots+n
Big hint:
Divide the sum by the number nn of terms
Solution:
The sum of the first nn positive integers is n(n+1)2.\frac{n(n+1)}{2}. Dividing by nn gives the mean n+12. \frac{n+1}{2}.
Therefore, the correct answer is E.
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