1959 AMC 12 Problem 29
Attempt Problem 29 of the 1959 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1959 AMC 12 solutions, or check the answer key.
All problems are used with official legal permission of the Mathematical Association of America (MAA).
29.
On an examination of questions a student answers correctly of the first Of the remaining questions he answers one third correctly. All the questions have the same credit. If the student’s mark is how many different values of can there be?
the problem cannot be solved
Answer: D
Small hint:
Express the total number correct in terms of
Big hint:
Set equal to
Solution:
The score condition gives Multiplying by yields so This value also makes the number of remaining correct answers an integer. Hence there is exactly one possible value of
Therefore, the correct answer is D.
Problem 29 in other years
- 1950 AMC 12
- 1951 AMC 12
- 1952 AMC 12
- 1953 AMC 12
- 1954 AMC 12
- 1955 AMC 12
- 1956 AMC 12
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- 1958 AMC 12
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