1960 AMC 12 Problem 29

Attempt Problem 29 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

29.

Five times AA’s money added to BB’s money is more than $51.00.\$51.00. Three times AA’s money minus BB’s money is $21.00.\$21.00. If aa represents AA’s money in dollars and bb represents BB’s money in dollars, then:
a>9,a\gt9, b>6b\gt6
a>9,a\gt9, b<6b\lt6
a>9,a\gt9, b=6b=6
a>9,a\gt9, but we can put no bounds on bb
2a=3b2a=3b
Answer: A
Concepts:inequalitysystem of equationsmoney
Small hint:
Use 3a−b=213a-b=21 to express bb in terms of aa
Big hint:
Substitute into 5a+b>515a+b>51
Solution:
From 3a−b=21,3a-b=21, we have b=3a−21.b=3a-21. Substitution into the inequality gives 5a+3a−21>51, 5a+3a-21>51, so a>9.a>9. It follows that b=3a−21>6.b=3a-21>6.
Thus, the correct answer is A.
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