1986 AMC 12 Problem 29

Attempt Problem 29 of the 1986 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AMC 12 solutions, or check the answer key.

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29.

Two of the altitudes of the scalene triangle ABCABC have length 44 and 12.12. If the length of the third altitude is also an integer, what is the biggest it can be?
44
55
66
77
none of these
Answer: B
Concepts:triangle inequalityaltitudeareareciprocal relation
Small hint:
For a fixed triangle area, each side is inversely proportional to its corresponding altitude
Big hint:
Apply the triangle inequalities to side lengths proportional to 14,112,1h\frac{1}{4},\frac{1}{12},\frac{1}{h}
Solution:
Let the third altitude be h.h. Since each side equals twice the common area divided by its altitude, the side lengths are proportional to 14,112,1h. \frac14,\qquad\frac1{12},\qquad\frac1h. The two nontrivial triangle inequalities give 1h<14+112=13,1h>14−112=16. \begin{aligned} \frac1h&\lt\frac14+\frac1{12}=\frac13,\\ \frac1h&\gt\frac14-\frac1{12}=\frac16. \end{aligned} Thus 3<h<6.3\lt h\lt6. The largest integral possibility is 5,5, and its three altitudes are distinct as required for a scalene triangle.
Therefore the correct answer is B.
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